The correct answer is C. Now: sin 6θ = 3 sin 2θ − 4 sin 3 2θ = (3 − 4 sin 2 2θ) ⋅ sin 2θ 16[sin 2θ + cos 4θ + sin 6θ]

If then is equal to:

Maths Trigonometrical Ratios, Functions and Identities JEE Mains 2021 Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 12, 2026

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Text Solution

Verified by Experts

The correct answer is:

Now:

sin 6θ = 3 sin 2θ − 4 sin 3 2θ

= (3 − 4 sin 2 2θ) ⋅ sin 2θ

16[sin 2θ + cos 4θ + sin 6θ]

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